(4x^2-7x+2)+(5x^2+7x-2)=0

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Solution for (4x^2-7x+2)+(5x^2+7x-2)=0 equation: 



(4x^2-7x+2)+(5x^2+7x-2)=0

We get rid of parentheses

4x^2+5x^2-7x+7x+2-2=0

We add all the numbers together, and all the variables

9x^2=0

a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{18}=0$

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